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Components of physiccs

  1. Oct 2, 2006 #1
    the question i got was:
    will the horizontal and vertical components of a vector at 45degrees to the horizontal be larger or smaller than the vector? By how much?

    so far this is what i understand the vertical and horizontal components form a right angle and the vector is the line in the middle. and what im guessing is that the horizontal component and the vector form a 45 degree angle..but thats all i understood so far...please help!
     
  2. jcsd
  3. Oct 2, 2006 #2
    if you imagine an XY coordinate system, imagine laying the vector on the x-axis then moving it up 45 degrees (its tail at the origin and arrow pointing down the positive x-axis). that is all it is. the way to represent the x/y components of this vector is to make a triangle out of it (with the vector being the hypotenuse). The x component is simply the base of the triangle and the Y component is the height. With a 45 degree angle the x/y components will be the same.

    to find the x component of the vector take the cos(angle)*vector or sin(angle)*vector for the y component. In the case of 45 degrees the x/y components will be about 70.7% of what the vector will be
     
  4. Oct 2, 2006 #3
    thanks man
     
  5. Dec 7, 2008 #4
    yeah...sorry, but i dont get this..a little help?
    (im only in 7th grade tho, so lamens terms plz)
     
  6. Dec 7, 2008 #5
    the angle is at 45°, then the resultant is the square root of 2 which equals 1.41 units. Since both sides will be 1 unit long the resultant will be 0.41 units LARGER.
    hope this helps! :)
     
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