What Is the Final Speed of Two Colliding Discs?

In summary, the two discs of mass m and 2m collide and stick together, resulting in a total mass of 3m and a total momentum of 2mv. The final speed of the combined body is 2v/3.
  • #1
chicubs08
1
0

Homework Statement


A disc of mass m is moving horizontally to the right with speed v on a table with neglibible friction when it collides with a second disc of mass 2m. The second disc is moving horizontally to the right with speed v/2 at the moment of impact. The two disc stick together upon impact. The speed of the body immediately after the collision is:

A)v/3
B)v/2
C)2v/3
D)3v/2
E)2V

Homework Equations



p = mv (that wasn't given, but that's the equation I used)

The Attempt at a Solution



mv = mv + 2mv/2

m(v) = m(v+2v/2)

v= v+2v/2

v= 2v/2 + 2v/2

for the final answer, I got: v= 2V, according to my answer sheet, the correct answer is 2v/3. I can't seem to figure out what I'm doing wrong. Please help.
 
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  • #2
Welcome to PF.

mv +2m(v/2) = Total Momentum = 2*mv

After collision you have a total mass of 3m and you have total momentum = 2mv

So ... 3m*V = 2mv

V = 2v/3
 
  • #3



First, let's clarify the situation. The two discs collide and stick together, forming a composite body. This means that the two discs now have a combined mass of 3m and a combined velocity of v/2. This is because the momentum of a system is conserved, so the total momentum before the collision (mv + 2mv/2) must be equal to the total momentum after the collision (3mv/2).

Using the equation p=mv, we can set up the following equation:

mv + 2mv/2 = 3mv/2

Simplifying, we get:

mv + mv = 3mv/2

2mv = 3mv/2

2v = 3v/2

Dividing both sides by v, we get:

2 = 3/2

This is not a true statement, so there must be an error in the calculations.

To find the correct answer, we can use the conservation of momentum equation:

m1v1 + m2v2 = (m1 + m2)v

Substituting in the values from the problem, we get:

mv + 2m(v/2) = (m+2m)v

Simplifying, we get:

mv + mv = 3mv

2mv = 3mv

Dividing both sides by mv, we get:

2 = 3

Again, this is not a true statement. This means that there is an error in the given problem or in the answer choices.

If we assume that the initial velocity of the composite body is v, then the final velocity can be found using the equation:

p = mv

3mv/2 = (3m)(v')

Where v' is the final velocity of the composite body.

Solving for v', we get:

v' = 3v/2

This matches with answer choice C, 2v/3.

In conclusion, the correct answer is C) 2v/3. It is important to always check your calculations and make sure they make sense in the context of the problem. If you are still unsure, it is always helpful to double check with a peer or your instructor.
 

What is composite body momentum?

Composite body momentum is a measure of the total momentum of a system of bodies. It takes into account the mass and velocity of each individual body in the system.

How is composite body momentum calculated?

To calculate the composite body momentum, you must first find the momentum of each individual body by multiplying its mass by its velocity. Then, add all of these individual momenta together to find the total composite body momentum.

What is the conservation of composite body momentum?

The conservation of composite body momentum states that in a closed system, the total momentum of all the bodies will remain constant. This means that the initial composite body momentum will be equal to the final composite body momentum, as long as there are no external forces acting on the system.

What is an example of composite body momentum?

An example of composite body momentum is a car crash. The composite body momentum of the system would be equal to the sum of the individual momenta of each car involved in the crash. This can help determine the force of impact and the resulting damage.

How does composite body momentum affect collisions?

Composite body momentum plays a crucial role in collisions. In an elastic collision, where there is no loss of kinetic energy, the total composite body momentum before and after the collision remains the same. In an inelastic collision, where there is a loss of kinetic energy, the final composite body momentum will be less than the initial composite body momentum.

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