Hmm why wouldn't it work??Fredrik said:What TenaliRaman suggested doesn't work. f is definitely not a polynomial. (Try f(x)=x and f(x)=x² and you'll see the problems immediately).
If you include an x^2 term in f(x) you get an x^4 term in f(f(x)).TenaliRaman said:Hmm why wouldn't it work??
-- AI
the coefficient of x^4 could be zero ....Fredrik said:If you include an x^2 term in f(x) you get an x^4 term in f(f(x)).
It was definitely not my day!matt grime said:only if the coefficient of x^2 were zero.
sqr(2)x+jXamfy19 said:What is the f, when f(f(x)) = 2x^2 - 1,
Thanks alot!!!