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Composite Functions

  1. Sep 18, 2009 #1
    f o g (x) = Abs(x)
    f(x)=?
    g(x)= root(x)

    im thinking f(x) is = to root(x) correct me if im wrong?
     
  2. jcsd
  3. Sep 18, 2009 #2

    Mark44

    Staff: Mentor

    f(x) = sqrt(x) doesn't work. Are you sure you have this problem written correctly? Could it be g o f (x) = Abs(x)? That would make more sense with g(x) being sqrt(x). Of if it is indeed f o g (x) = Abs(x), could it be that f(x) = sqrt(x) and you need to find g(x)?
     
  4. Sep 18, 2009 #3
    its correct way i took it straight from the book.
     
  5. Sep 18, 2009 #4

    Mark44

    Staff: Mentor

    OK.
    If f(x) = x2 and g(x) = [tex]\sqrt{x}[/tex]
    then [itex](f~\circ~g )(x) = x[/itex].

    Since the domain of g = {x | x [itex]\geq [/itex] 0}, then x = |x| in this case.
     
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