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Compound pendulum question

  1. Apr 12, 2016 #1
    • Thread moved from the technical forums, so no HH Template is shown.
    I am doing the compound pendulum experiment but I am stuck on how to find the value of g from the graph

    Here's a description of the compound pendulum:

    The compound pendulum AB is suspended by passing a knife edge through the first hole. The pendulum is pulled aside through a small angle and released, whereupon it oscillates in a vertical plane with a small amplitude. The time for 10 oscillations is measured. From this the period T of oscillation of the pendulum is determined.

    The method to find the acceleration due to gravity, is not really making much sense.

    Please see it below:

    A graph is drawn with the distance d of the various holes a straight line is drawn parallel to the X- axis from a given period T on the Y- axis, cutting the graph at four points A, B, C, D. The distances AC and BD, determined from the graph, are equal to the corresponding length l. The average length l = (AC+BD)/2. In a similar way , l/T2 is calculated for different periods by drawing lines parallel to the X-axis from the corresponding values of T along the Y- axis. l/T2 should be constant over all periods T, so the average over all suspension points is taken. the acceleration due to gravity is calculated from the equation g= 4π2(l/T2).

    I don't know what the given period is, do you just use any random period? For I/T2, do you just like draw vertical lines parallel to all the values of T and then average the T values?
     
  2. jcsd
  3. Apr 12, 2016 #2

    mfb

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    2016 Award

    Staff: Mentor

    This would so be so much easier to understand with a sketch of the setup and a picture of the graph.
     
  4. Apr 12, 2016 #3
    I won't be able to upload a sketch of the setup since my printer isn't working at the moment.

    Is it okay if I show you an accurate picture of the experiment and a picture of the graph? :smile:
     
  5. Apr 12, 2016 #4

    berkeman

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    Staff: Mentor

    That's a good start! :smile:
     
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