(adsbygoogle = window.adsbygoogle || []).push({}); Little help in compound pendulum

1. The problem statement, all variables and given/known data

there is an equilateral triangle T with sides of length B. Suspend this triangle from a pivot throught on of its corners, so that it is free to swing about this corner in the plane of the tringle.

I want to ask how to compute the density p(x,y) and the R whcih from the pivot point to the center of gravity of the triangle.

In fact I found the soluation, but I don't know it is right or not.

Could anyone check it with me?

2. Relevant equations

p(x,y)=m/A

3. The attempt at a solution

A=sqrt(3)/4 * B^2

therefore p(x,y)=(4*sqrt(3)*m)/(3*B^2)

about the R:

cos 30 = sqrt(3)/2

R = (B/2)*(2/sqrt(3)) = (sqrt(3)*B)/3

did I make any mistake??

Thanks a lot

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# Homework Help: Compound pendulum

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