A compressed spring that obeys Hooke's law has a potential energy of 18 J . If the spring constant of the spring is 400 N/m, find the distance by which the sping is compressed.
Please correct me if I am wrong, I'm not sure how find the distace.
My work: k 400 N/m x=18J = 400 N/m/18 J = 0.045
But I think my answer has to be in cm, or m. please help.
Please correct me if I am wrong, I'm not sure how find the distace.
My work: k 400 N/m x=18J = 400 N/m/18 J = 0.045
But I think my answer has to be in cm, or m. please help.