A vertical spring with k = 495 N/m is standing on the ground. You are holding a 5.8 kg block just above the spring, not quite touching it. How far does the spring compress if you let go of the block suddenly? i thought i could just use k = F/distance so 495(D) = (5.8)(9.8) D = .1148 but this is not correct. i take it i am doing something wrong with my acceleration but i'm not sure what. can anyone help me with this?