The springs of a 1100 kg car compress 6.0 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, what will be the frequency of vibrations? I tried to use the weight of the man (68 kg) and the compression distance (6 mm) to find the spring constant. I then tried to use the spring constant to find the period. F = kx 68 = 6k k = 11.33 T = 2(pi)(sq.rt 1100/11.33) But I didn't get the correct answer.