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J89
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Homework Statement
Suppose 7.00 g of hydrogen is separated into electrons and protons. Suppose also the protons are placed at the Earth's North Pole and the electrons are placed at the South Pole. What is the resulting compressional force on the Earth?
Homework Equations
Fe = Ke*|q1||q2|/r^2, radius of Earth is 6.38*10^6 * 2 to get diameter is 1.3*10^7...
The Attempt at a Solution
I believe this is the correct way:
7 * 6.02^1023 = 4.21*10^24 (since it is 7 hydrogens, and 1 hydrogen = 1 Avagrado's number)
= [(4.21*10^24)*(1.60*10^-19)]^2/(4^(6.38*10^6)^2) * 8.99*10^9 = 2.51*10^7. I think the reason we multiply by 4 is because we need to get the diameter for both proton and electron, giving 4.
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