# Compton Collision

1. Oct 22, 2008

### Quelsita

Suppose that after a Compton collision between a photon and electron initially at rest, the electron and photon emerge symmetrically (in equal and opposite angles).
If the initial energy of the photon=30 keV, a) what is the angle that corresponds to such scattering? and b) what is the final photon energy? c) final electron energy?

1. If the angle of deflection is symmetric, then theta=180?

2. since we know theta, we can use
(delta)lambda=(h/mec)(1-cos(theta))
where =(h/mec) is the compton wavelength=0.02426A
which can be rearranged
hc/(delta)E=(0.02426A)(1-cos(theta))
and plug in theta and the Eiphoton to find the final energy.

3. Due to conservation of enery the total energy lost for the photon must equal that of the energy gained by the electron and we know Eiphoton and Efphoton this would equal (delta)Eelectron.

Is this correct?

2. Oct 23, 2008

### alphysicist

Hi Quelsita,

I don't believe this is correct; because

$$\Delta \lambda \neq \frac{hc}{\Delta E}$$

I would suggest finding the final wavelength (not using the $\Delta$ form) and then converting that to energy.