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## Homework Statement

A 650-keV gamma ray Compton-scatters from an electron. Find the energy of the photon scattered at 110°, the kinetic energy of the scattered electron, and the recoil angle of the electron.

## Homework Equations

Compton effect equation:

Δλ = [itex]λ^{'}[/itex] - λ = (h/mc) (1-cosθ)

Conservation of Energy:

hf + m[itex]c^{2}[/itex] = h[itex]f^{'}[/itex] + [itex]E_{e}[/itex]

hf is initial photon energy, m[itex]c^{2}[/itex] is electron energy before scattering, h[itex]f^{'}[/itex] is the energy of scattered photon with new frequency f prime, and [itex]E_{e}[/itex] is the energy of the recoil electron with mc^2 and Kinetic Energy.

## The Attempt at a Solution

First of all I am confused about the question. Are they saying a gamma ray is scattered? Or does a gamma ray hit the electron producing a scattering photon and the electron recoils?

For now, I am thinking that the gamma ray hits the electron (the latter mentioned).

For the recoil angle, I am thinking that it should be 80° since momentum is conserved and so the electron goes in the opposite direction, so 80°.

To find the energy of scattered photon I need to find the new frequency. My thought is that I need to find the new wavelength so that I can use f=c/λ. I can find the new wavelength using Compton Effect equation shown above. I know θ is 110°, and h,m,c are constants. But what about initial λ? Can I get that from the 650-keV? So E = 650-keV = hc/λ using h in terms of eV I can get λ. Right? Now I am all set to find the new wavelength.With that I can find the new frequency, and then find the scattering energy of the photon.

Now I should have all the information to find the Kinetic Energy using the Conservation of energy equation above.

Am I going the right way, any comments would be appreciated. Thanks! :)