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asdf12312
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Homework Statement
Photons of wavelength 59.0 pm are Compton-scattered from a free electron in an aluminum block, at 87.0° from the original direction. What energy (in electronvolts) has been imparted to each electron?
Homework Equations
[itex]\frac{h}{mc}[/itex] = 0.0024nm for e-
∇λ = [itex]\frac{h}{mc}[/itex] (1-cosθ)
hc = 1240 eV*nm
The Attempt at a Solution
I got as answer: 2.02 [itex]\times[/itex] 104eV (its wrong):
∇λ = 0.0024nm *(1-cos(87°)) = 0.0023nm
λ2 = λ1+∇λ = 0.059nm + 0.0023nm = 0.0613nm
E2 = hc/λ2 = 1240eV*nm / 0.0613nm = 2.02 [itex]\times[/itex] 104eV
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