(adsbygoogle = window.adsbygoogle || []).push({}); Compute the flux of neutrinos arriving at Earth, i.e. the number of neutrions that land on each square meter of Earth's surface each second.

The question is referring to neutrinos created in the photon-photon chain in the Sun.

I already computed that the Sun releases [tex]1.78*10^{38}[/tex] neutrinos per second in the photon-photon chain.

So 1 square meter, if face-on to the Sun at Earth's distance should intercept[tex]\frac{1}{4 \pi r^2}*1.78*10^{38} [/tex] neutrinos per second, where r is 149598000000 the radius of Earth's orbit in meters.

So, 1 square meter, if face-on to the Sun at Earth's distance should intercept [tex]6.33*10^{14} neutrinos/s[/tex]

I have a feeling that this is the answer the teacher will consider correct. However, not all square meters on Earth's surface are face-on to the Sun. Only square meters where the Sun is directly overhead will receive a full dosing of [tex]6.33*10^{14} neutrinos/s[/tex]. Square meters of Earth's surface where the Sun is setting or rising should receive 0 neutrinos (consider the Sun a point or a whole new can of worms is opened!)

All points inbetween will receive anywhere between 0 and [tex]6.33*10^{14} neutrinos/s[/tex].

But the change from minimum to maximum not a linear function, so I can't just average it. What would I use to compute the average flux? Can I avoid integrating? This class is supposed to avoid Calculus, but I have a feeling the integration in this case is easy since it is related only to SIN.

Any thoughts?...

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# Homework Help: Compute the Flux of Neutrinos

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