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when n goes from 1 to oo of

1/(n^2(2n-1))

So far this is what i've done

1/(n^2(2n-1))=4/(2n(2n-1))-1/n^2

I know the sum from 1 to oo of 1/n^2 =(pi^2)/6

So I get

1/(n^2(2n-1))=4/(2n(2n-1)) - pi^2/6

so I need to compute the sum of 4/(2n(2n-1)) which i have no idea how to do.

Any hints or tips would be great

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# Compute the sum

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