Compute the following sum(adsbygoogle = window.adsbygoogle || []).push({});

when n goes from 1 to oo of

1/(n^2(2n-1))

So far this is what i've done

1/(n^2(2n-1))=4/(2n(2n-1))-1/n^2

I know the sum from 1 to oo of 1/n^2 =(pi^2)/6

So I get

1/(n^2(2n-1))=4/(2n(2n-1)) - pi^2/6

so I need to compute the sum of 4/(2n(2n-1)) which i have no idea how to do.

Any hints or tips would be great

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Compute the sum

Loading...

Similar Threads - Compute | Date |
---|---|

I How do we compute an integral with a dot product inside ? | Dec 30, 2016 |

I Computing the normal scalar component of acceleration | Apr 5, 2016 |

A nasty integral to compute | Jan 20, 2016 |

How to compute the surface height based on normal vectors | May 12, 2015 |

Computing an integral -- any method | Apr 18, 2015 |

**Physics Forums - The Fusion of Science and Community**