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Compute this limit

  1. Sep 14, 2008 #1
    please help me and compute this limit:
    llim x^1/x when x approaches infinite.
    I think we can rewrite this so: e^ln (x^1/x).
  2. jcsd
  3. Sep 14, 2008 #2
    ok so it simplifies to e^((lnx)/x) and the limit of (lnx)/x is 0, so??? e^0 = 1
  4. Sep 15, 2008 #3
  5. Sep 15, 2008 #4
    it was very easy!!:smile:
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