1. The problem statement, all variables and given/known data y = x 2sinx 2. Relevant equations 3. The attempt at a solution Ok, so If I see an x in an exponent, I would want to use ln to 'bring it out', right? ln y = ln (x 2sinx) = ln x + ln 2sinx = ln x + sinx ln2 now I take the derivative : y'/y = 1/x + cosx ln2 multiply both sides by y y' = [1/x + cosx ln2] (x 2sinx) is everything correct?