1. The problem statement, all variables and given/known data Just checking if these are right? f(b) = 2-2√b compute limit in are as: b-> 0+ b->1- Explain in a brief sentence why it does not make sense to compute a limit as b->0- 2. Relevant equations given above 3. The attempt at a solution lim b->0+ (2-2√b) = 2 lim b->1- (2-2√b) = 0 Lim b->0- (2-2√b) = ? The question says it doesn't make sense to do so. Is it not 2?