(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A concave spherical mirror has a radius of curvature of magnitude 27.1 cm.Determine the object position for which the resulting image is inverted and larger than the object by a factor of 4.00.

2. Relevant equations

Mirror equation in terms of focal length: 1/p + 1/q = 1/f

3. The attempt at a solution

I'm not getting the correct answer for this question. Here's what I've done so far:

First we find the focal length

[tex]f=\frac{R}{2} \implies \frac{27.1}{2}=13.55 \ cm[/tex]

[tex]M = \frac{-q}{p}=4 \implies q=-4p[/tex]

Substituting in

[tex]\frac{1}{p} - \frac{1}{4p} = \frac{1}{13.55}[/tex]

[tex]\frac{3}{4p} = \frac{1}{13.55} \implies p =10.162[/tex]

I don't know why the answer is wrong. I know that image is inverted when Magnification is negative. Here it is not -ve because the questions says "larger" so I took it as positive...

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# Homework Help: Concave Spherical Mirrors

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