- #1

I am new in this forum and really hope that somebody can help me.

I would like to show that the following function in concave of convex so I need to calculate the second derivative of Q(t) :

Q(t)=Integral[upper=T; Lower=0]{tF(t)q(p-st)}dt

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- Thread starter gohou@econ.umd.edu
- Start date

- #1

I am new in this forum and really hope that somebody can help me.

I would like to show that the following function in concave of convex so I need to calculate the second derivative of Q(t) :

Q(t)=Integral[upper=T; Lower=0]{tF(t)q(p-st)}dt

- #2

HallsofIvy

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If [tex]Q(t)= \int_0^t (\tauF(\tau)q(p-s\tau))d\tau[/tex]

then the best I can do is

[tex]\frac{dQ}{dt}= tF(t)q(p-st)[/tex]

(by the fundamental theorem of calculus) without knowing what F is. (And is q a constant or a function?)

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