What is the concentration of Br1- ions in a solution of 0.0330% AlBr3?

In summary, to calculate the concentration of Br1- ions expressed in ppm from a solution that is 0.0330% by weight AlBr3, it is necessary to make assumptions about the density of the solution. The solution can be assumed to have a density of 1.00 g/mL, which can be used to convert the given weight percentage to grams per 100 mL of solution. From there, the number of moles of AlBr3 can be calculated and converted to moles of Br1- ions, which can then be expressed in moles per liter and multiplied by 10^6 to get the concentration in ppm. It is important to use the same number of significant digits as given in the initial weight percentage.
  • #1
Benzoate
422
0

Homework Statement



A solution is found to be 0.0330% by weight AlBr3. What is the concentration of the Br1- ion expressed in ppm?

Homework Equations





The Attempt at a Solution



Assume .0330 % => .0330 g AlBr3

.0330 g AlBr3*(1 mol AlBr3/266.697 g AlBr3)*(3 mol Br^-1 /1 mol AlBr3) =.0003712 mol Br^-1

10^6 g sol'n *(1 mL/1.0 g sol'n)*(1 L/1000^3) = 1000 L

(.0003712 mol Br^-1) /(1000 L) = 3.712*10^-6
 
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  • #2
Start over.

The percent of AlBr3 is grams per 100 grams of solution. You need to make an assumption that this low concentration (0.0330%) will yield a solution with a density of approximately 1.00 g/mL. (so 0.00330 g AlBr3/100g solution = 0.0330 g AlBr3/100 mL)

Since the concentration is given with a specific number of significant digits, use the same number of significant digits in your answer.
 
  • #3
chemisttree said:
Start over.

The percent of AlBr3 is grams per 100 grams of solution. You need to make an assumption that this low concentration (0.0330%) will yield a solution with a density of approximately 1.00 g/mL. (so 0.00330 g AlBr3/100g solution = 0.0330 g AlBr3/100 mL)

Since the concentration is given with a specific number of significant digits, use the same number of significant digits in your answer.

don't you mean 0.00330 g AlBr3/100g solution = 0.00330 g/100 mL
AlBr3 not 0.00330 g AlBr3/100g solution = 0.0330/100 mL g AlBr3

Anywh, would you now multily (.00330 g AlBr3/100 g AlBr3)*(1 mol AlBr3 /266.68 g AlBr3)*(3 mol Br1-/1 mol AlBr3) to get the number of moles of Br1- ions? If I followed the correct procedure, would divide my number of bromine moles by 10^6 g to calculate the concentration?
 
  • #4
Benzoate said:
don't you mean 0.00330 g AlBr3/100g solution = 0.00330 g/100 mL AlBr3 not 0.00330 g AlBr3/100g solution = 0.0330/100 mL g AlBr3

No. I mean 0.0330 g aluminum bromide per one hundred milliters of solution. In shorthand it looks like this: 0.0330 g AlBr3/100 mL solution.

Benzoate said:
Anywh, would you now multily (.00330 g AlBr3/100 g AlBr3)*(1 mol AlBr3 /266.68 g AlBr3)*(3 mol Br1-/1 mol AlBr3) to get the number of moles of Br1- ions? If I followed the correct procedure, would divide my number of bromine moles by 10^6 g to calculate the concentration?

Nope. If there are 0.0330 g AlBr3 per 100 mL of solution, how many grams of AlBr3 will there be in a liter? You need to express the number of moles of Br- in terms of moles per liter and then multiply by 10^6. You need to do a little work to convert percent to moles per liter... but you must do it. Try multiplying the percentage by ten and see where that leads. (since 10 X 100 mL is 1000 mL or one liter)
 

1. What is a concentration ion problem?

A concentration ion problem is a type of problem that involves calculating the concentration of ions in a solution. It typically involves using the molar concentration of a compound and its dissociation constant to determine the concentration of each individual ion in the solution.

2. How do you solve a concentration ion problem?

To solve a concentration ion problem, you will need to first identify the compound and its dissociation constant. Then, you will need to use the molar concentration and dissociation constant to set up an equation, which can be solved using algebraic methods. Finally, you can use the solution to calculate the concentration of each individual ion in the solution.

3. What are some common mistakes made when solving concentration ion problems?

Some common mistakes made when solving concentration ion problems include using incorrect values for the dissociation constant or molar concentration, not considering the charge of the ions when setting up the equation, and not properly accounting for the stoichiometry of the reaction. It is important to double check all values and calculations to avoid these errors.

4. How do temperature and pressure affect concentration ion problems?

Temperature and pressure can affect concentration ion problems by altering the dissociation constant of the compound, which can then impact the concentration of each individual ion in the solution. It is important to use the correct dissociation constant for the given temperature and pressure to ensure accurate calculations.

5. What are some real-world applications of concentration ion problems?

Concentration ion problems have many real-world applications, including in environmental science, pharmaceuticals, and water treatment. They can be used to determine the concentration of pollutants in water, calculate the correct dosage of medication, and ensure safe and effective water treatment processes.

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