1. The problem statement, all variables and given/known data Object A and B are placed on a spring. Object A has twice as much mass as object B. If the spring is depressed and released, propelling the objects into air, object A will: answer: rise to the same height as object B 2. Relevant equations 3. The attempt at a solution Based on my reasoning and math, I am confused why both objects would rise to the same height: The force on both objects is the same, F. And 2*mass of B = mass of A F = (mass of A)*(accl. A) = (mass of B)*(accl. B) F = 2*(mass of B)*(accl. A) = (mass of B)*(accl. B) cancel out (mass of B): F = 2*(accl. A) = (accl. B) Since the upward acceleration of B is twice the that of A, why would the height be the same?