Concept of L-C circuits

  • Thread starter 2RIP
  • Start date
  • #1
62
0
Hello,

This is just a conceptual question I have for the image below.
http://img22.imageshack.us/img22/7489/44840348.jpg [Broken]

If the switch is turned off at t=0, why is the voltage across the voltmeter=20V? I understand that current in all inductors is zero. But wouldn't at t=0, current would need to pass through the first resistor, and therefore a voltage has dropped making voltmeter reading less than 20V?

Thank you in advance.
 
Last edited by a moderator:

Answers and Replies

  • #2
318
0
First consider a simple LC curcuit. Apply kisrchoff's and solve the differential equation for current. You will get that An inductor behaves like infinite resistance at t=0 and a pure conductor at t=infinity. Form this i think that you would be able to solve the problem

And just for extra information: A capictor behaves like a pure conductor at t=0 and as an infite resistance at t=infinity
 

Related Threads on Concept of L-C circuits

  • Last Post
Replies
6
Views
900
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
2
Views
921
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
4
Views
3K
Top