- #1
Winner
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Hey ,
The question:
The athlete on the diagram (linked) is free in the air and has a total angular momentum as indiated by the red vector.
1)Indicate with a vector the direction of his twist based on his orientation and angular momentum, show how you got this.
2)Describe 2 different movements he could make to stop his twisting while in the air, explain.
Link here:
http://www.geocities.com/saint_biron/gymrotate.JPG"
1)By dividing the angular momentum into it's parts, I can get the rotation about each axis, as I've done.
So with the horizontal axis, and USING the right hand rule (ie thumb points in directin of angular momentum, and fingers wrap around axis, or rotate in that direction. The horizontal axis will be rotation backwards and the vertical axis is rotating clockwise?
2)I think you can stop the movement by raising the right hand or dropping the left hand. But are these different? They work because that way, the body position is symmetrical and the angular momentum in each axis is 0?
Thanks
The question:
The athlete on the diagram (linked) is free in the air and has a total angular momentum as indiated by the red vector.
1)Indicate with a vector the direction of his twist based on his orientation and angular momentum, show how you got this.
2)Describe 2 different movements he could make to stop his twisting while in the air, explain.
Link here:
http://www.geocities.com/saint_biron/gymrotate.JPG"
1)By dividing the angular momentum into it's parts, I can get the rotation about each axis, as I've done.
So with the horizontal axis, and USING the right hand rule (ie thumb points in directin of angular momentum, and fingers wrap around axis, or rotate in that direction. The horizontal axis will be rotation backwards and the vertical axis is rotating clockwise?
2)I think you can stop the movement by raising the right hand or dropping the left hand. But are these different? They work because that way, the body position is symmetrical and the angular momentum in each axis is 0?
Thanks
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