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Condensator question

  1. May 12, 2008 #1
    1. The problem statement, all variables and given/known data

    Doubling the potential over a condensator, results in...

    a) doubling the capacitance
    b) halving the capacitance
    c) doubling the charge



    3. The attempt at a solution

    Since C = Q/V, it's got to be either b) or c). But which?
     
  2. jcsd
  3. May 12, 2008 #2

    Borek

    User Avatar

    Staff: Mentor

    Hint: capacitance is defined ONLY by the capacitor geometry and dieletric constant of spacer between plates.

    And this is hardly advanced physics, I would classify it as introductory.
     
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