box A contains 2 red balls,(adsbygoogle = window.adsbygoogle || []).push({});

box B contains 2 white balls,

box C contains 1 red ball and 1 white ball,

A box is selected at random (with equal probabilities) and one ball is taken at random from that box.

(i) Compute the probability of selecting a white ball using Bayes Rule.

A(1/3) _____ Red(1/6)

.........|____ Red(1/6)

B(1/3)______White(1/6)

........|_____White(1/6)

C(1/3)______Red(1/6)

........|_____White(1/6)

so.. P(White) = [(1/3)*(1/6)] + [(1/3)*(1/6)] + [(1/3)*(1/6)]

= 1/6

Correct?

(ii)Compute the conditional probability that B has been selected given that the ball is white.

P(B|White) = P(B intersect White) / P(White)

what is my P(B intersect White)?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Conditional Probability (ii)

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