- #1
Pure Canuck
- 1
- 0
Hey guys Me and my friend just got this question and it seems easy but i just want to make sure we are right anyway here it is:
A road has two stoplights at consecutive intersections. The prob. of a red at the first is 0.55 and the probability of a green at the second, give a green at light oine is .75
Find the prob of a green at both intersections:
Givens = (r1 = .55) (g2|g1=.75)
now i believe its simply as just r1*.75.
which is like .33
Anybody know if i did this right?
Thanks
A road has two stoplights at consecutive intersections. The prob. of a red at the first is 0.55 and the probability of a green at the second, give a green at light oine is .75
Find the prob of a green at both intersections:
Givens = (r1 = .55) (g2|g1=.75)
now i believe its simply as just r1*.75.
which is like .33
Anybody know if i did this right?
Thanks