• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Conduction and displacement current density

  • Thread starter tiagobt
  • Start date
Could anyone help me solve the following problem?

Calculate the ratio of the conduction current density to the displacement current density of the electric field [itex]E = E_0 \cos(\omega t)[/itex] in copper, to a frequence of [itex]f = 1 kHz[/itex]. (Given: [itex]\epsilon_{Cu} = \epsilon_0[/itex], [itex]\rho_{Cu} = 2 \times 10^{-8} \Omega m[/itex]).​

First, I calculated the displacement current density:

[tex]J_d = \epsilon_{Cu} \frac {dE} {dt} = - \epsilon_0 E_0 \sin(\omega t)\omega[/tex]

I'm not sure if it's correct. Besides, I don't know how to find the conduction current density. I thought about using:

[tex]\vec{\nabla} \times \vec{B} = \mu_0 (\vec{J} + \epsilon_0 \vec{J_d})[/tex]

But is there a magnetic field? I'm confused...
 
Last edited:

Want to reply to this thread?

"Conduction and displacement current density" You must log in or register to reply here.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top