The temperature in an electric oven is 160 °C. The temperature at the outer surface in the kitchen is 38.6 °C. The oven (surface area = 1.44 m2) is insulated with material that has a thickness of 0.0249 m and a thermal conductivity of 0.0405 J/(s m C°). (a) How much energy is used to operate the oven for 3.88 hours? (b) At a price of $0.10 per kilowatt-hour for electrical energy, what is the cost (in dollars) of operating the oven?(adsbygoogle = window.adsbygoogle || []).push({});

OK I know to use the Conduction of Heat Through A material on this problem

Q = (k A Delta T) t/ L

After plugging in my values Q = [.045 J/ (s.m.C (degrees)] (1.44m ^2) (160 degrees - 38.6 degrees)(13968 sec) (hours converted to seconds) / 0.0249 m

I get my answer to be 4412945.581 J? This should be my energy value right? The Q in this case is my energy expenditure?

I plugged this answer in for the webbased solution but it was incorrect.

Thanks for ur help

Jason:tongue:

**Physics Forums - The Fusion of Science and Community**

# Conduction problem

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Conduction problem

Loading...

**Physics Forums - The Fusion of Science and Community**