1. The problem statement, all variables and given/known data An isolated capacitor with capacitance C = 1 µF has a charge Q = 22 µC on its plates. Now a conductor is inserted into the capacitor. The thickness of the conductor is 1/3 the thickness of the capacitor and is centered in between the plates of the capacitor. What is the capacitance of the capacitor with the conductor in place? 2. Relevant equations Q = C / V V = E d 3. The attempt at a solution I know that since the capacitor is a conductor it makes the distance between the two plates smaller which means that the capacitance should therefore increase. I thought that since we now had two distances that were each 1/3 the original distance the capacitance would increase by a factor of 6 however this answer does not work. Can anyone help me please?!?