# Conductor in Capacitor

1. Sep 17, 2008

### voelkner

1. The problem statement, all variables and given/known data

An isolated capacitor with capacitance C = 1 µF has a charge Q = 29 µC on its plates

A conductor is inserted into the capacitor with thickness of the conductor is 1/3 the thickness of the capacitor and is centered in between the plates of the capacitor.

What is the capacitance of the capacitor with the conductor in place???

2. Relevant equations

C = Q/V

V = E*d

3. The attempt at a solution

I've been trying this problem for hours. I know that since the capacitor is a conductor it makes the distance between the two plates smaller which means that the capacitance should therefore increase. I thought that since we now had two distances that were each 1/3 the original distance the capacitance would increase by a factor of 6 however this answer does not work. Can anyone help me?!?

2. Sep 17, 2008

### tiny-tim

Hi voelkner!

6 = 3 + 3 … isn't that for capacitors in parallel?

these capacitors are in series.

3. Sep 17, 2008

### voelkner

Would it then be 1/C?

4. Sep 17, 2008

### tiny-tim

1/C = 1/C1 + 1/C2