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Conductor in Capacitor

  1. Sep 17, 2008 #1
    1. The problem statement, all variables and given/known data

    An isolated capacitor with capacitance C = 1 µF has a charge Q = 29 µC on its plates

    A conductor is inserted into the capacitor with thickness of the conductor is 1/3 the thickness of the capacitor and is centered in between the plates of the capacitor.

    What is the capacitance of the capacitor with the conductor in place???

    2. Relevant equations

    C = Q/V

    V = E*d

    3. The attempt at a solution

    I've been trying this problem for hours. I know that since the capacitor is a conductor it makes the distance between the two plates smaller which means that the capacitance should therefore increase. I thought that since we now had two distances that were each 1/3 the original distance the capacitance would increase by a factor of 6 however this answer does not work. Can anyone help me?!?
     
  2. jcsd
  3. Sep 17, 2008 #2

    tiny-tim

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    Hi voelkner! :smile:

    6 = 3 + 3 … isn't that for capacitors in parallel?

    these capacitors are in series. :smile:
     
  4. Sep 17, 2008 #3
    Would it then be 1/C?
     
  5. Sep 17, 2008 #4

    tiny-tim

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    1/C = 1/C1 + 1/C2 :wink:
     
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