1. The problem statement, all variables and given/known data An isolated capacitor with capacitance C = 1 µF has a charge Q = 29 µC on its plates A conductor is inserted into the capacitor with thickness of the conductor is 1/3 the thickness of the capacitor and is centered in between the plates of the capacitor. What is the capacitance of the capacitor with the conductor in place??? 2. Relevant equations C = Q/V V = E*d 3. The attempt at a solution I've been trying this problem for hours. I know that since the capacitor is a conductor it makes the distance between the two plates smaller which means that the capacitance should therefore increase. I thought that since we now had two distances that were each 1/3 the original distance the capacitance would increase by a factor of 6 however this answer does not work. Can anyone help me?!?