The Plane z=0 forms an interface between two conductors of conductivity σ1 and σ2 respectively. In the 1st conductor a steady current J1 flows and it makes an angle θ1 with the normal of the interface. Find the current in the 2nd conductor and the charge density on the interface.
The Attempt at a Solution
I don't know the shapes of the conductors and for some reason this poses a problem for me. I know that from Ohms lawJ = σE, so the current and the electric field are in the same direction. I see no reason why the second current shouldn't be just
J2 = σ2E where the electric field is the one from the 1st current ( unless there should be a contribution from the field from the interface...?! )
Any help will be much appreciated. Thank you!