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gneill said:Another approach is to imagine a voltage source V across the terminals and solve the loop equations for the current in the voltage source loop. The ratio V/I is the equivalent resistance.
gneill said:Imagine: pretend; postulate; suppose
builder_user said:I mean in equatations.
Use U or some "image U(E)"?
gneill said:I meant to suggest that you imagine that you've connected a voltage source V (or U, or E, or whatever variable name you wish) at the open terminals where you want to find the resistance. If you solve for the current that this voltage produces, then you can find the resistance as V/I.
builder_user said:I still don't understand.Sth like this?
gneill said:Yes, exactly.
builder_user said:But how can it help?What loop includes E?
A!I see now.gneill said:E --> R3 --> R4 --> back to E
builder_user said:A!I see now.
What's with 5# scheme?
builder_user said:Can I do like that?
When I find I2-I3=I(on R=30 Ohms) will be I=U2/R(30)?
gneill said:What happened to diagonal resistor R4?.
builder_user said:Delta-y transformation
builder_user said:When I find I1 && I2 then I can find I3.I3*R(30)=U2 right?
builder_user said:Does it mean that if I have such circuit(pic.) current i throught R1 exists but when circuit does not have R1 there is no current i?
builder_user said:Here
builder_user said:It is U like U2(or U1) in previous circuit
gneill said:In the previous circuit you're looking for a relationship between U1 and U2. That means, if you put a real source (say V1) where U1 is, you want to find what the open-terminal voltage is at the terminals U2. In such a case the terminals at U2 are open -- not connected to anything (except perhaps a voltmeter!). So no current will flow through U2.
Alternatively, you could put a real voltage source (say V2) where U2 is, and measure the resulting voltage at the U1 terminals. Again, in such a case the terminals at U1 would be open -- not connected to anything, and no current would flow there.
builder_user said:А!There is no current if I have voltage source in the circuit?
builder_user said:When i=0?
gneill said:No current flows through an open circuit. If the terminals at U are open, then current i = 0.
To determine the equivalent resistance in a circuit with multiple resistors, you can use the formula Req = R1 + R2 + ... + Rn, where Req is the equivalent resistance and R1, R2, ... , Rn are the individual resistances. Alternatively, you can use the parallel and series combination rules to simplify the circuit and calculate the equivalent resistance.
Yes, it is possible to transform a circuit with resistors in parallel to one with resistors in series. This can be done by using the parallel and series combination rules to simplify the circuit. However, the equivalent resistance may not be the same as the original circuit.
The purpose of transforming a circuit to one resistor is to simplify the circuit and make it easier to analyze. This can be especially useful when dealing with complex circuits with multiple resistors, as it allows for easier calculation of current, voltage, and power.
Yes, it is possible to transform a circuit with only one resistor to one with multiple resistors. This can be done by using the series and parallel combination rules to add additional resistors to the circuit. However, the equivalent resistance may not be the same as the original circuit.
Transforming a circuit to one resistor can either increase or decrease the overall resistance, depending on the original circuit and the transformation used. For example, transforming a circuit with resistors in parallel to one with resistors in series will increase the overall resistance, while transforming a circuit with resistors in series to one with resistors in parallel will decrease the overall resistance.