(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

I need to prove that if two metrics are related by an overall conformal transformation of the form [tex]\overline{g}_{ab}=e^{a(x)}g_{ab}[/tex] and if [tex]k^{a}[/tex] is a killing vector for the metric [tex]g_{ab}[/tex] then [tex]k^{a}[/tex] is a conformal killing vector for the metric [tex]\overline{g}_{ab}[/tex]

2. Relevant equations

killing equation

killing conformal equation

3. The attempt at a solution

i think i need to show that

[tex]\overline{\nabla}_{a}k_{b}+\overline{\nabla}_{b}k_ {a}=(k^{r}\nabla_{r}a(x))\overline{g}_{ab}[/tex]

which as far as i understand is the killing conformal equation for the metric [tex]\overline{g}_{ab}[/tex]

so using the relation [tex]\overline{\nabla}_{a}k_{b}=\nabla_{a}k_{b}-C^{r}_{ab}k_{r}[/tex]

where [tex]C^{r}_{ab}[/tex] are the connection coefficients for the conformal transformation, i.e., if [tex]\overline{g}_{ab}=\omega^{2}g_{ab}[/tex] then:

[tex]C^{r}_{ab}=\omega^{-1}(\delta^{r}_{a}\nabla_{b}\omega+\delta^{r}_{b}\nabla_{a}\omega-g_{ab}g^{rc}\nabla_{c}\omega)[/tex] if i substitute this in [tex]\overline{\nabla}_{a}k_{b}+\overline{\nabla}_{b}k_ {a}[/tex]

and use killing equation for the metric [tex]g_{ab}[/tex] i obtain:

[tex]\overline{\nabla}_{a}k_{b}+\overline{\nabla}_{b}k_{a}=-k_{a}\nabla_{b}a(x)-k_{b}\nabla_{a}a(x)+(k^{r}\nabla_{r}a(x))g_{ab}[/tex]

which is not the conformal killing equation for [tex]\overline{g}_{ab}[/tex] so im lost , can anyone help me on this?

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# Homework Help: Conformal Transformation of the metric (General Relativity)

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