- #1

Alem2000

- 117

- 0

[tex]\Phi=\oint _\mathcal{S} \mathbf{E}\cdot d\mathbf{a} = \frac{q_{enc}}{\epsilon _0}[/tex]

and since electric field is the flux over the area i can find it by

[tex]E=\Phi/A[/tex]

so shouldn't I be able to find the position fo the charge from

[tex]\Phi/A=q/4\pi r^2 \epsilon_0[/tex]

this is really confusing, do I have the theory wrong?