Confused about Flux

  • Thread starter Alem2000
  • Start date
  • #1
Alem2000
117
0
I was a bit confused by a homwork problem that I was working on. The problem is that I found the flux of a charge and I know the demsions of the Gaussian surface it is encolsed in. It doesn't seem right intuitively to be able to find the location of the charge from this information...but mathmatically I am thinking I can solve for r.
[tex]\Phi=\oint _\mathcal{S} \mathbf{E}\cdot d\mathbf{a} = \frac{q_{enc}}{\epsilon _0}[/tex]
and since electric field is the flux over the area i can find it by
[tex]E=\Phi/A[/tex]
so shouldn't I be able to find the position fo the charge from
[tex]\Phi/A=q/4\pi r^2 \epsilon_0[/tex]
this is really confusing, do I have the theory wrong?
 

Answers and Replies

  • #2
Crosson
1,259
4
Yes, you have two different definitions for flux:

[tex] \Phi = E A [/tex]

and

[tex]\Phi=\oint \vec{E}\cdot \vec{da} [/tex]

Notice how the second definition is a generalization of the first one. The first equation only applies to flat surfaces which are perpendicular to the field, the second definition works in general.

Also, the r that you pulled out of Gauss' law is the radius of a spherical Gaussian surface (an hence the place you are looking at the field) , not "the distance to the charge".
 
  • #3
Alem2000
117
0
THANK YOU, that makes a lot more sense now!
 

Suggested for: Confused about Flux

Replies
9
Views
332
Replies
42
Views
874
Replies
6
Views
103
  • Last Post
Replies
1
Views
486
Replies
9
Views
291
Replies
12
Views
659
Replies
7
Views
407
Replies
8
Views
497
  • Last Post
Replies
7
Views
535
Top