(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

δu/δt+2tδu/δx=1

for t>0,x>0 with u= 0 on x= 0 for t>0, u=1 at t=0 for x≥0

2. Relevant equations

3. The attempt at a solution

((dx)/(dt))=2t

x=t²+c

x-t²=c

the general solution is:

u=t+F(x-t²)

Now i am confused about the terminology for the domain, ie it says it is defined for t>0, x>0

I am confused about u= 0 on x= 0 for t>0

0=t+F(-t²)

thus it follows that u(x,t)=t-√(t²+x)

"at" x=o

But what does it mean when is states this is only for t>0. For all t>0 when x is zero u will be zero anyway.

The answer shows that the funcrtion u is equal to what i have solved for t²>x,

and i can see that in this case the square root is defined(ie not √-)

Then from the second condition the solution shows that u=1+t for t²≤x

I would basically like to understand all this properly as i always get a bit confused with inequalities. How did they apply the second condition and inequality to get the second function and what was the reasoning?

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# Confused about the terminology for the domain pde

Can you offer guidance or do you also need help?

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