I need help in understanding back emf, I'm a bit confused here. Example(for understanding): Let's assume we have a 12 V DC motor, that draws 20Amps when it starts, as it reaches maximum speeds, current drops due to back emf, lets assume the resistance is 0.6 ohms, and b.emf = 10V. Vtot = 2V ,from ohms law I can find the current at maximum speed, it would now be I = V/R = 3.3Amps Now what about power? Initial power = 240W Power at max rpm = 6.6W? Will the motor be stable at 2V at maximum speeds? Or will it draw more voltage because of the b.emf and stay the same rate of power @ 240W with lower current? (here is where I'm struggling). If everything above correct?