- #1
awl2k
- 1
- 0
Hello people!
I am having a bit trouble with verifying my result when i compute the eigenvectors for the following matrix:
A=[[3,4],[3,2]]
I know for sure that the eigenvalues is respectively -1 and 6, so i start finding a solution for the following null spaces:
1) N(A--1I)=[[4,4|0],[3,3|0]]~[[1,1|0],[0,0|0]] => x1 = x2 so the the vector x2[1,-1] will be a solution and therefor the first eigenvector is [1,-1]
2) N(A-6I)=[[-3,4|0],[3,-4|0]]~[[1,-4/3|0],[0,0|0]] => x1=4/3 so this indicate that x2[-4/3,1] will be a solution to the null space, and therefor the second eigen vector i [-4/3,1].
However the result should be [1,-1] [4,3] respectively. What am i doing wrong?
I am having a bit trouble with verifying my result when i compute the eigenvectors for the following matrix:
A=[[3,4],[3,2]]
I know for sure that the eigenvalues is respectively -1 and 6, so i start finding a solution for the following null spaces:
1) N(A--1I)=[[4,4|0],[3,3|0]]~[[1,1|0],[0,0|0]] => x1 = x2 so the the vector x2[1,-1] will be a solution and therefor the first eigenvector is [1,-1]
2) N(A-6I)=[[-3,4|0],[3,-4|0]]~[[1,-4/3|0],[0,0|0]] => x1=4/3 so this indicate that x2[-4/3,1] will be a solution to the null space, and therefor the second eigen vector i [-4/3,1].
However the result should be [1,-1] [4,3] respectively. What am i doing wrong?