Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Confusing 2-norm proof

  1. Apr 21, 2012 #1
    I don't understand how you're supposed to prove this:

    Let A=uvT (vT = v transpose) where u is in R^M and v is in R^N. Prove 2-norm of A = 2 norm of v * 2 norm of u.

    I'm not sure if I'm supposed to look at v and u as vectors or what. If they are just vectors, this does not make any sense. I'm assuming the only way this is even possible is if v is a collection of m different vectors each of length n, which would just make v a matrix. Am I missing something here?
  2. jcsd
  3. Apr 21, 2012 #2


    User Avatar
    Science Advisor
    Homework Helper

    It does make sense if u and v are vectors. The product
    $$\begin{bmatrix} u_1 \\ u_2 \\ \cdots \\ u_m \end{bmatrix}
    \begin{bmatrix} v_1 & v_2 & \cdots & u_n \end{bmatrix}$$ is an m-by-n matrix.

    Since there is nothing special about u and v, the only thing you have to work with here is the definition of the 2-norm. Start by multiplying out the matrix, and writing down the values of the three 2-norms.
  4. Apr 21, 2012 #3
    I see what you mean, I was looking at u as a row vector rather than a column vector, which makes multiplication impossible. I multiplied out the matrix, but I'm stuck from here. I can't really use the 2-norm of a matrix since I don't know any of the eigenvalues. What is your tip from here? I didn't quite know what you meant by the "three 2-norms."
    Last edited: Apr 21, 2012
  5. Apr 21, 2012 #4


    User Avatar
    Science Advisor
    Homework Helper

    Ahh .... there are too many different definitions of "norm"!

    I took the question as meaning the 2-norm of a matrix is
    $$\sqrt{\sum_i \sum_j |a_{ij}|^2 }$$
    and the 2-norm of a vector is
    $$\sqrt{\sum_i |a_{i}|^2 }$$
    (i.e. the Frobenius norm). By "the three 2-norms" I just meant the 2-norms of the two vector, and the matrix.
  6. Apr 21, 2012 #5
    The 2-norm of a matrix is different from the Frobenius norm of a matrix and the proof involves the 2-norm of A, which is a matrix. If the proof were to show equality of the Frobenius norm and the product of the two vector norms, this would make more sense. However, it's for the 2-norm of A.
  7. Apr 21, 2012 #6


    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    You have a rank 1 matrix and you don't know any of the eigenvalues?
  8. Apr 22, 2012 #7


    User Avatar
    Science Advisor
    Homework Helper

    I can think of several definitions of a norm that could be reasonably be called "the 2-norm of a matrix". I can only say what I think the question means, because I don't know what terminology your course is using.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook