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Confusing question in Differential first order

  1. Mar 28, 2012 #1
    I have a first order ODE of the form
    dy/dx = F(ax+by+c)/(Ax+By+C) ---> (a,b,c,A,B,C all non zero constants)

    Under what condition, does there exist a linear substitution that reduces the equation to one in which the variables are separable?

    (A) Never
    (B) if aB = bA
    (C) if bC = cB
    (D) if cA = aC

    Ans: I feel it is (B). But there are unclear doubts. My attempt goes below

    if a/A != b/B
    I am aware that if a/A != b/B, then I can convert this non-homogeneous eqn into homogeneous
    1) by eliminating the constants c and C using ah+bk+c=0 and Ah+Bk+C=0 and substituting x with X+h and y = Y+k. Then eqn reduces to the form (aX+bY)/(AX+BY).
    2) further by substituting V=Y/X, I can convert the given eqn into a variable separable one.

    if a/A = b/B
    But if a/A = b/B(= t say) still I can write it as dy/dx = [t(Ax+By) + c]/(Ax+By+C) and then substituting U for Ax+By (a linear substitution), it again becomes of the form
    (1/b)(dU/dx - A)= (tU+c)/U+C
    which again is variable separable.

    This is the doubt,
    I have done linear substitution in both the cases (x = X+h and y = Y+k) and have obtained the eqn in variable separable form. So aB = bA is not the only condition, it may as well be aB!=bA. Can anyone clarify?
  2. jcsd
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