How is it that [tex]\pi\^{\pm}[/tex] have charges [tex]\pm e[/tex] and [tex]\pi\^{0}[/tex] has a charge of 0? The [tex]\pi\^{+}[/tex] has one up quark and an anti-down quark, which doesn't add up to zero (same deal goes for [tex]\pi\^{-}[/tex], and the [tex]\pi\^{0}[/tex] has a linear combination that doesn't seem to add up to zero.(adsbygoogle = window.adsbygoogle || []).push({});

Where have I gone wrong?

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# Confusion on Pion Charges

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