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Confusion on Pion Charges

  1. Oct 1, 2008 #1
    How is it that [tex]\pi\^{\pm}[/tex] have charges [tex]\pm e[/tex] and [tex]\pi\^{0}[/tex] has a charge of 0? The [tex]\pi\^{+}[/tex] has one up quark and an anti-down quark, which doesn't add up to zero (same deal goes for [tex]\pi\^{-}[/tex], and the [tex]\pi\^{0}[/tex] has a linear combination that doesn't seem to add up to zero.

    Where have I gone wrong?
     
  2. jcsd
  3. Oct 1, 2008 #2

    malawi_glenn

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    pi + has as you say, one up and one anti-down which gives you +2/3 + 1/3 = 1

    You are saying (The [tex]\pi ^+[/tex]
    has one up quark and an anti-down quark, which doesn't add up to zero ) But the pi + should have CHARGE = 1e!! As you said in the sentence before this one.

    Maybe try to be more consistent to yourself.. try again.
     
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