Adjacent anti-nodes of a standing wave are 7m apart. The amplitude is 0.5m and period 0.05 seconds. Assuming the string is clamped at the position x=0m, y=0m on the left hand side.
Find the amplitude at the point 0.29 m from the right of an antinode
y=ASin(ωt-kx) ? (Moving to the right, as clamped on the left?)
The Attempt at a Solution
Well at first i did
x position = λ/4 + 0.29 = (adjacent nodes are 7m apart, so λ=14) 14/4 + 0.29= 3.79m
v = λ/T = 14/0.05 = 280 m/s
hence t=d/v = 3.79/280 = 0.0135 seconds
y = ASin[(2pi/T)t-(2pi/λ)x] = 0.5sin(0)
Which I know must be wrong becuase it will be zero at a node, an that is not a node (3.5m is a node).
Im unsure what is wrong with my method though :S