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Congruent Triangle in circle

  1. Apr 2, 2007 #1
    [​IMG]

    Sorry, it's upside down :(

    How do i go about solving A. I know that for somthing to be congruent it needs to

    SSS
    RHS
    AAS
    SAS

    I know that C = B because they lie on a circuference and a chord that binds them is A. Where do I go from now?

    Thx
     
  2. jcsd
  3. Apr 2, 2007 #2

    cristo

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    Staff Emeritus
    Science Advisor

    What does this mean?
     
  4. Apr 2, 2007 #3
  5. Apr 2, 2007 #4
    Angles pcb and pbc are also equal (alternate angle theorem). Therefore, pc=pb (sides opp equal angles). This gives you two sides equal and 1 side common so sss congruency is established.
     
  6. Apr 3, 2007 #5
    I dont see how it's alternate segment theory...

    I cant see it. Do you know a good technique for spotting it?

    Thx
     
  7. Apr 7, 2007 #6
    If you extend pc to some point, say q. Then angle acq is equal to angle abc. Apply the same thing on the other side of the quad.
     
  8. Sep 7, 2010 #7
    OKay, this is my thinking
    statement 1: AP=AP Reason: common line (S)
    statement 2: <ABC = <ACB reason: given
    statement 3: <PBC = <PCB reason: tangent from the same point P
    statement 4: therefore <ABP = <ACP reason: see statement 2&3 (A)
    statement 5: <CPA = <BPA reason: tangent cords are from the same point P (A)
    statement 6: triangle ABP = triangle ACP reason: AAS

    but I'm not sure for statement 5, as the diagram doesn't indicate anything...
     
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