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## Homework Statement

I have : (x)^2+(2xy)+y^2+2(2)^(1/2)x−2(2)^(1/2)y+4=0

Now when I use the rotation formulas I get : y'=(x'^2)/2 + 1

But I don't know if this makes sense....

## Homework Equations

tan2β=B/(A−C)

x=x'cos β - y'sin β

y=x'cos β + y'sin β

## The Attempt at a Solution

We know that β= pi/4 because B/(A−C) tends towards infinity.

So we replace pi/4 in

x=x'cos β - y'sin β

y=x'cos β + y'sin β

and put those in the long equation and simplify. Which gives us y'=((x'2)/2)+1

Does this make sense my answer

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