Lab: Conical Pendulum - Understanding A & Unit

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In the lab discussion on the conical pendulum, the relationship between the period (T) and the length of the string (L) is expressed as T = A√L. The value A represents a constant that has units of time multiplied by the inverse square root of length. Specifically, the dimensions of A are time per length to the power of negative one-half. Participants also noted the importance of using proper formatting for mathematical expressions in the forum. Understanding the value and units of A is crucial for accurately interpreting the results of the experiment.
Helenah
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Moved from a technical forum, so homework template missing
So I'm doing a lab in class, and when I graphed the Period vs Length of the string, I got it in the form $T=A\sqrt{L}$, but I don't really know what the value $A$ represents nor what its unit is... Can someone help me?
 
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Hello Helenah, :welcome:
Helenah said:
So I'm doing a lab in class, and when I graphed the Period vs Length of the string, I got it in the form $T=A\sqrt{L}$, but I don't really know what the value $A$ represents nor what its unit is... Can someone help me?
Would you know the answer for a simple pendulum ?

T is time, L is length, so for your A you have [A] = ##\rm {time} \; {length}^{-{1\over 2}} ##

( So what is the dimenson of 1/A2 ? )And: in PF you get in-line math using the tags ## and displayed math using the tags $$
instead of a single $ sign.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

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