# Conical Pendulum units problem

Hello all , I encouter a problem solving this one :

We are given a conical pendulum with : V - tan. speed of particle
m - mass of rotating particle
g - gravity acceleration
L - leght of the string

We need to find CosA , T by what is given above !!!
A- is the angle between the string and vertical line !!!!

So : I wrote : tcosA=mg
tsinA=mv^2/R
R=LsinA

but I can't present cosA without sinA or something

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sAXIn said:
So : I wrote : tcosA=mg
tsinA=mv^2/R
R=LsinA
That's fine. You can simplify and solve for T. Use the 3rd equation to eliminate R from the 2nd equation. Then realize that $\sin^2\theta = 1 - \cos^2\theta$.

okay got it I get 2nd order eq.
thanks a lot