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**Conics!!! Help Please!!!!**

okay i think i have solved this correctly...still a little unsure though....

y=x^2-6x+3----find x intercept

first i used complete the square---- y-3=(x-3)^2

then i solved for x---- 3+(y-3)^(1/2)=x

then i plugged 0 in for y and got 3+(3^(1/2)) and 3-(3^(1/2))

is that correct??