- #1
emohunter7
- 19
- 0
Conics! Help Please!
okay i think i have solved this correctly...still a little unsure though...
y=x^2-6x+3----find x intercept
first i used complete the square---- y-3=(x-3)^2
then i solved for x---- 3+(y-3)^(1/2)=x
then i plugged 0 in for y and got 3+(3^(1/2)) and 3-(3^(1/2))
is that correct??
okay i think i have solved this correctly...still a little unsure though...
y=x^2-6x+3----find x intercept
first i used complete the square---- y-3=(x-3)^2
then i solved for x---- 3+(y-3)^(1/2)=x
then i plugged 0 in for y and got 3+(3^(1/2)) and 3-(3^(1/2))
is that correct??