- #1

- 279

- 0

## Homework Statement

http://img103.imageshack.us/img103/3784/arch3tf0.jpg [Broken]

[/URL]## Homework Equations

On picture above

## The Attempt at a Solution

Again, I just want someone to check my work.

Last edited by a moderator:

- Thread starter temaire
- Start date

- #1

- 279

- 0

http://img103.imageshack.us/img103/3784/arch3tf0.jpg [Broken]

[/URL]On picture above

Again, I just want someone to check my work.

Last edited by a moderator:

- #2

- 238

- 0

c=distance from center to focii, a = distance from center to vertex

Incidentally, you don't need to calculate for a since it's given.

- #3

- 238

- 0

Whoops, I realized that the problem is using a different form of the vertical hyperbola instead of [tex]\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1[/tex], so in this case switch a and b. In the other problem, where b=10 is correct.

Last edited:

- #4

- 279

- 0

- #5

- 238

- 0

- #6

- 279

- 0

We haven't used the terms focus or focii with these problems in class. What do you mean by them?

- #7

- 279

- 0

Do you mean the center?

- #8

- 238

- 0

In a parabola, the there is only one focus. Since this parabola opens down, then the focus is at (h,-c+k).

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 11

- Views
- 4K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 5

- Views
- 1K

- Last Post

- Replies
- 11

- Views
- 2K

- Last Post

- Replies
- 6

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 2K