- #1

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[tex]\prod_{i=1}^{n}A_{i} = F_{2^{n+1}}[/tex]

or if someone has already proven this, can you give the reference?

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- Thread starter ramsey2879
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- #1

- 841

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[tex]\prod_{i=1}^{n}A_{i} = F_{2^{n+1}}[/tex]

or if someone has already proven this, can you give the reference?

- #2

- 841

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Note of is relation can be found at the first comment re the sequence 3,7,47 .... See http://www.research.att.com/~njas/sequences/A001566" [Broken], but I would like a proof if it is known.

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- #3

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[tex]

F_{2n}=L_{n}F_{n}

[/tex]

[tex]

L_{2n}=L_{n}^{2}-2(-1)^{n}

[/tex]

Where [tex]L_n[/tex] is the nth Lucas numbers.

- #4

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Where can I find a proof of those identities?

[tex]

F_{2n}=L_{n}F_{n}

[/tex]

[tex]

L_{2n}=L_{n}^{2}-2(-1)^{n}

[/tex]

Where [tex]L_n[/tex] is the nth Lucas numbers.

- #5

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